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student2280

Please help quick

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解答 0

  • eric
    2019-05-20 19:27:34
    24. Use tan2θ=2tanθ/(1-tan^2 θ)
  • eric
    2019-05-20 20:02:34
    26. Use cos(4θ) = cos^4(θ) - 6cos2^(θ)sin2(θ) + sin^4(θ) and (sin^2(θ)+cos^2(θ))^2=1
  • eric
    2019-05-20 20:08:07
    28a. Expand 3/(csc^2(θ)+1) using sin2θ formula
  • eric
    2019-05-20 20:09:31
    28b. Use the range of csc^2(θ)
  • eric
    2019-05-20 20:14:18
    Use the minimum of csc^2(2θ)
    •  eric 2019-05-20 20:09:31
    • 28b. Use the range of csc^2(θ)
  • student2280
    2019-05-21 16:18:32
    I have used ,but i dont know how to do the next step
    •  eric 2019-05-20 19:27:34
    • 24. Use tan2θ=2tanθ/(1-tan^2 θ)
  • student2280
    2019-05-21 16:38:59
    I dont know how to use the range
    •  eric 2019-05-20 20:09:31
    • 28b. Use the range of csc^2(θ)
  • eric
    2019-05-21 16:41:36
    2tanθ/(1-tan^2 θ)=√3 √3tan^2 θ+2tanθ-√3=0 Then solve for tanθ
    •  student2280 2019-05-21 16:18:32
    • I have used ,but i dont know how to do the next step
  • student2280
    2019-05-21 16:46:35
    I dont know how to do the next step

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    •  eric 2019-05-20 20:08:07
    • 28a. Expand 3/(csc^2(θ)+1) using sin2θ formula
  • eric
    2019-05-21 16:48:01
    the range of csc^2(2θ) is 1 to ∞ Substituting 1 into the expression will give the answer
    •  student2280 2019-05-21 16:38:59
    • I dont know how to use the range
  • eric
    2019-05-21 16:59:23
    the second last step is wrong as sin^2(2θ)=4sin^2(θ)cos^2(θ)
    •  student2280 2019-05-21 16:46:35
    • I dont know how to do the next step
  • student2280
    2019-05-21 17:16:15
    Thank a lots
  • student2280
    2019-05-21 17:16:32
    Thank a lot
  • eric
    2019-05-21 17:18:52
    Not at all
    •  student2280 2019-05-21 17:16:32
    • Thank a lot
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