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Hayley

Polynomials

How to do? Clear steps plz

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解答 0

  • tayh
    2019-06-02 20:53:26
    a. f(x+1)=(x+1)^99
    (x+1)^99=xQ(x)+R
    代x=0, 求得R=1

    b. From(a), remainder is 1 when (x+1)^99 div by x
    Put x=8, it becomes
    remainder is 1 when (8+1)^99 div by 8
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