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QBillie

Solve identities

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  • eric
    2019-12-03 23:46:14
    Sin3x=1 3x=π/2,5π/2,9π/2 x=π/6,5π/6,3π/2
  • QBillie
    2019-12-04 00:07:35
    Sorry, I don’t understand the part where you separated 3x and x And isnt 5π/2 and 9π/2 not special angles?
    •  eric 2019-12-03 23:46:14
    • Sin3x=1 3x=π/2,5π/2,9π/2 x=π/6,5π/6,3π/2
  • eric
    2019-12-04 01:21:59
    X between 0 and 2π, so 3x between 0 and 6π, and sin3x=1 gives the 3 answers as shown above
    •  QBillie 2019-12-04 00:07:35
    • Sorry, I don’t understand the part where you separated 3x and x And isnt 5π/2 and 9π/2 not special angles?
  • eric
    2019-12-04 09:40:05
    3x are special angles, x not neccessary be
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