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student17175

Form 5 maths circle

Can you please help me with Qs28?

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  • eric
    2019-12-11 22:28:04
    ∠CEA=∠EFA, ∠ACE=180°-∠ACB =180°-∠PAB =∠FAP =∠AEF
  • student17175
    2019-12-12 00:40:47
    Can you write a full set of solutions and steps for me please!
    •  eric 2019-12-11 22:28:04
    • ∠CEA=∠EFA, ∠ACE=180°-∠ACB =180°-∠PAB =∠FAP =∠AEF
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