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Chanzhiyi

arithmetic sequence

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  • 解數雜貨店
    2020-08-15 23:13:50
    a) b/a = c/b log b/a = log c/b log b - log a = log c - log b bi) Verify if log b² - log a² = log c² - log b² bii) Assume they are in AS log (b+k) - log (a+k) = log (c+k) - log (b+k) log (b+k)/(a+k) = log (c+k)/(b+k) (b+k)/(a+k) = (c+k)/(b+k) b²+2bk+k² = ac+(a+c)k+k² 2b = a+c 2 = a/b + c/b 2 = b/c + c/b b and c can be any number. If we choose b/c as 2, then the equality doesn’t hold. So, we conclude that our assumption is not correct. They are not in AS
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