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Yannes

26b

a係-1 b點做?

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解答 0

  • eric
    2020-09-09 20:57:43
    b. =[(2-sqrt5)(2+sqrt5)]^(2n-1)/(2-sqrt5)
  • eric
    2020-09-09 20:59:47
    Correction: =(2-sqrt5)[(2-sqrt5)(2+sqrt5)]^(2n-1)
    •  eric 2020-09-09 20:57:43
    • b. =[(2-sqrt5)(2+sqrt5)]^(2n-1)/(2-sqrt5)
  • eric
    2020-09-09 21:00:33
    as a correction to the first one
    •  eric 2020-09-09 20:59:47
    • Correction: =(2-sqrt5)[(2-sqrt5)(2+sqrt5)]^(2n-1)
  • 解數雜貨店
    2020-09-09 21:07:09
    (2-√5)[(2-√5)(2+√5)]²ⁿ⁻¹ = (2-√5)(-1)²ⁿ⁻¹ = -(2-√5) = √5-2
  • Yannes
    2020-09-09 21:13:32
    I don’t understand the first step. Thank you
  • 解數雜貨店
    2020-09-09 21:21:06
    Write a = 2-√5, b = 2+√5 (a²ⁿ)(b²ⁿ⁻¹) = (a²ⁿ⁺¹⁻¹)(b²ⁿ⁻¹) = (a.a²ⁿ⁻¹)(b²ⁿ⁻¹) = a(a²ⁿ⁻¹.b²ⁿ⁻¹) = a(ab)²ⁿ⁻¹
  • leung_po_chuen
    2020-09-09 21:47:22
    如果要用a的結果

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